8^(3x+5)=(1/4)^(x-2)

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Solution for 8^(3x+5)=(1/4)^(x-2) equation: 



8^(3x+5)=(1/4)^(x-2)

We move all terms to the left:

8^(3x+5)-((1/4)^(x-2))=0



Domain of the equation: 4)^(x-2))!=0

x∈R



We add all the numbers together, and all the variables

8^(3x+5)-((+1/4)^(x-2))=0

We multiply all the terms by the denominator


(8^(3x+5))*4)^(x+1-2))-((=0

We add all the numbers together, and all the variables

(8^(3x+5))*4)^(x-1))-((=0

We add all the numbers together, and all the variables

(8^(3x+5))*4)^(x=0

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